Thread: Asteroid Driver View Single Post

 cfuruti Member Join Date: Jun 2009 Posts: 441 Total Downloaded: 436.34 MB
Quote:
 Originally Posted by Damraska The spun section provides 15,700 square feet of space under artificial gravity, equivalent to about 8 moderately sized homes. I have not done calculations for the rate of spin but estimate this cylinder should provide constant gravity equivalent to one fourth Earth normal, enough to stave off the debilitating effects of prolonged life in micro-gravity.
(sorry, I'm used to international units) If
• the inner radius of the spinning section is r meters
• the desired pseudogravity is a m/s²
• the section spins at R rotations per minute,
The centripetal acceleration of constant circular motion is a = r omega², where omega is the angular velocity in rad/s.
rad/s = 2 pi RPM / 60,
therefore the acceleration at the "bottom" floor is a = r (2 pi RPM / 60)² = 4 pi² R² / 3600
And
• r = 900 a / (pi² R²)
• R = (30/pi) sqrt(a/r)
For instance, if you want a = g/4, about 2.5 m/s²,
• if R = 5 RPM, r should be about 9.13 m
• if r is 10 m, R should be about 4.78 RPM
Now you can estimate minimum RPM and radius for acceptable mechanical constraints and practical limits.