C-130 / AC-130 Hercules Redraw/Redesign (by Airdave)

[herky]

Originally Posted by airdave

Considering the fact that I am English, its surprising how few RAF models I have created!

I think I have two Mustangs and two Spits, but thats about it.

One reason is because when I started this I was only looking at colourful and/or
unique paint schemes, and the RAF planes tend to be all very similar. Its the US
that gave us all the pretty noseart and odd looking Assembly Planes. And its
other countries that use brighter and more distinct colours on their aircraft.

I think an RAF Herc is in order...especially since I have the Canadian versions.
Added to the list!

an easy one would the raf tanker version i have from corgi.its all a horrendous pinkisk coulour.i also have an old one that is raf support command brown camoflage .as well as that two tankers in falklands camo.if you want photos anytime i can do them for you

[thorst]

Originally Posted by herky

yup i remember taking an a4 model to library and asking them to print it a3.as has been said an a3 sheet is exactly twice the size of an a4 sheet but im sure they only blew it up around 40-50 percent.in my naievety i imagined that that it would just print out double size to fill paper

It's no secret:
A4->A3 means to double the area. Area is length multiplied by width, or

A=l*w

.
The fun working with DIN paper sizes is, that the length/width relation keeps constant through all sizes (every DIN A sheet looks the same format).
This means that by doubling the Area, the length and width are multiplied by the same factor:

2*A=(two times the area)=
   =f*l*f*w=(both length and width multiplied by the same factor f)=
   =f²*(l*w)=(f*f=f². Then l*w=A from above, which leads to:)=
   =f²*A

.
This means that

2=f²
f=square root of 2~1.41=141%

Printing a model for A4 on A3 paper leads to an enlargement of about 41%

Hope you excuse my travel into mathematics after wakeup ;-)
Thorsten

[herky]

Originally Posted by thorst

It's no secret:
A4->A3 means to double the area. Area is length multiplied by width, or

A=l*w

.
The fun working with DIN paper sizes is, that the length/width relation keeps constant through all sizes (every DIN A sheet looks the same format).
This means that by doubling the Area, the length and width are multiplied by the same factor:

2*A=(two times the area)=
   =f*l*f*w=(both length and width multiplied by the same factor f)=
   =f²*(l*w)=(f*f=f². Then l*w=A from above, which leads to:)=
   =f²*A

.
This means that
Printing a model for A4 on A3 paper leads to an enlargement of about 41%

Hope you excuse my travel into mathematics after wakeup ;-)
Thorsten

ok now my brain hurtsif a3 is double the area of a4 as we all know it is then how come you only an enlagrement of 41% when you print an a4 model onto a3.surely it should enlarge by 100% or am i missing something here?

[Vermin_King]

the surface area is 100% larger, but linearly only 41%

[herky]

Originally Posted by Vermin_King

the surface area is 100% larger, but linearly only 41%

thats the bit that confuses me.i believe you but dont understand it

[Vermin_King]

If you have a sheet of A4 and a sheet of A3, you can test it. Measure the length of one sheet and compare it to the length of the other

[airdave]

its simple...

bigger means larger
means more paper
means more ink
means more money
means more smiles
means less room in your mancave.

[airdave]

For those of you not satisfied with a paper Herc,
for $25 you can get a real one!!

Well, starting bid is $25, but they don't go for much more than that.

1 ea. (Approx 69000 lbs) Lockheed C-130 Model E Aircrafts (wings and electronics have been removed), located at 934th Ai - Government Liquidation

Complete with wings, engines, etc but it has been disassembled.
Only thing is, you can not remove the plane, and you cannot remove any parts.
You must destroy the entire thing on the property.

You see, the plane is actually just a crapload of scrap aluminium.
You can cut it up and shred it, for the aluminium.


...haha Herky got all excited

[herky]

dave ,you can go right off people you know

[airdave]

BIG (as in Wall size) Hercules update!

No...don't get excited.
Theres no Alan Rose DC3 style Herc coming!
At least not yet.
This is still a project that interests me, but its not at the top of my to-do list.

I've been asked a few times about the prospect of producing a large scale Hercules model in the same fashion as the Alan Rose DC3*
*6ft4" wingspan...just the front half of the Wings, nose and cockpit area sticking out of the Wall.

Although I do love the idea of a BIG scale Herc model, there are a number of difficult design challenges in converting the existing C-130 model.

But I am more concerned with the actual scale size.
Yes, a 6 foot (1829mm) wingspan is impressive...

but after calculating I realize the front fuselage, cockpit section of the model
will stick out from the wall 25.5 inches! (640mm)

Unlike the DC3, the Hercules Wings are set further back on the fuselage.
And the Fuselage is very long.

I just think this might make it an undesirable model for most.
And making it any smaller (in scale) would make the whole project pointless.
The existing 1/48 scale kit already has an impressive 33" wingspan.

And are there enough people interested in a "wall" version to make it a worthwhile project.
I think the answer was a resounding yes with the DC3...but maybe not with a Herc.
And the DC3 was free...but my big scale Herc will not be.

After checking some measures, I find that the Rose DC3 is about 21" deep.
I did not realize it was that large...and because of the scale differences between the two models, the 25.5" Herc does not seem as bad.

A 6'4" (wingspan) DC3 is roughly 1:14 scale

However, a 6'4" C-130 is about 1:21 scale


FYI a great build of the original Alan Rose kit HERE